find the rectangular dimension whose perimeter is 60 m and area is 200m sq
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Answer:
the dimensions are length=20m and breadth=10m
Step-by-step explanation:
area =200 m sq
length*breadth=200
breath = 200/length
putting the value of breadth in perimeter
2(l+200/l)=60
2(l²+200)=60l
2l²+400=60l
l²+200=30l
l²-30l+200=0
l²-20l-10l+200=0
l(l-20)+10(l-20)=0
(l+10)(l-20)=0
therefore l=-10, 20
since distance can never be negative so l=20m
putting the value of length in area l*b=200
20*b=200
b=200/20
b=10m
therefore length=20 and breadth=10
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