Find the relation between coefficients and zeros of the
polynomial x2–2x-8.
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Heya !!!
P(X) => X²-2X-8
=> X²-4X+2X-8
=> X(X-4) +2( X-4)
=> (X-4) (X+2) = 0
=> (X-4) = 0 OR (X+2) = 0
=> X = 4 OR X = -2
4 and -2 are the two zeroes of the polynomial X²-2X-8.
RELATIONSHIP BETWEEN THE ZEROES AND COEFFICIENT.
Sum of zeroes = Alpha + Beta = 4 + (-2) = 4-2 = 2/1 = Coefficient of X/Coefficient of X².
And,
Product of zeroes = Alpha × Beta = 4 × -2 = -8/1 = Constant term/Coefficient of X².
HOPE IT WILL HELP YOU...... :-)
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