Question

PQ is a tangent to the circle with centre at O, at the point B. If angle-AOB=100, then angle-ABP is equal to?

Answer 1

Answer:

50

Step-by-step explanation:

Answer 2

Given: PQ is a tangent to the circle, angle AOB=100

To find: angle ABP = ?

Solution:

• Now, considering the triangle formed AOB, we find that the sides are equal:

        OA = OB ........(radius of the circle)

• It indicates that the rest two angles are equal.

• Let the angles be x( since both are same)

• by angle sum property of a triangle, we get

        100° + x + x = 180°

        2x = 80°

        x = 40°

• Now, we know that PB is perpendicular to OB, as PQ is a tangent to circle and tangent is always perpendicular.

• So, ang OBP = 90°

        ang OBA + ang ABP = 90°

        40 + ang ABP = 90°

        ang ABP = 90° - 40°

        ang ABP = 50°

Answer:

           Therefore, angle ABP = 50°