Question

find the relation between solubility and solubility product for a2 b3 type salt

Answer 1

A-2
B-3

Therefore,(2S)^2 ×(3S)^3
=108S^5

Hope the steps are clear

Answer 2

The relation between solubility, [S] and its solubility product (ksp) for A₂B₃ type salt is - ksp = 108 x S⁵.

• A₂B₃ type salt on dissociation release two A³⁺ ions and three B²⁻ ions.
• Let [S] be the solubility of the salt.
• It can be written as-

        A₂B₃       →       2A³⁺ +  3B²⁻

                                  2[S]      3[S]

• Solubility product is denoted by ksp. It is the product of solubility of the ions of the salt.
• So, for  A₂B₃ type salt, ksp = [2S]² x [3S]³
• ksp = 4S² x 27S³
• ksp = 108 S⁵
• Solubility product of  A₂B₃ type salt = 108 x [solubility]⁵