Find the relation between x and y such that the points (x,y) is equidistant (5,2) and (2,3)
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Answer:
(x-5)^2 + (y -2)^2 = ( x-2)^2 +(y -3)^2
x^2 +25 -10x + y^2 +4 -4y = x^2 +4 -4x + y^2 +9 -6y
x^2 -x^2 + y^2- y^2-10x+4x-4y+6y +4 -9 + 25 -4 = 0
-6x +2y + 16 = 0
taking (- 2) common
3x- y -8 = 0
This is the relation between x and y
Answered by
0
Answer:
Answer:
(x-5)^2 + (y -2)^2 = ( x-2)^2 +(y -3)^2
x^2 +25 -10x + y^2 +4 -4y = x^2 +4 -4x + y^2 +9 -6y
x^2 -x^2 + y^2- y^2-10x+4x-4y+6y +4 -9 + 25 -4 = 0
-6x +2y + 16 = 0
taking (- 2) common
3x- y -8 = 0
This is the relation between x and y
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