Find the relation btn (x,y)as it is equidistant from (7,1) , (3,5)
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Let P(7,1) , R(3,5) and O(x,y) be the given coordinates.
As O(x,y) is equidistant from P(7,1) and R(3,5) :
PO = RO
=> √(7-x)²+(1-y)² = √(3-x)²+(5-y)²
=> √x²-14x+49+y²-2y+1 = √x²-6x+9+y²-10y+25
=> x²-14x+49+y²-2y+1=x²-6x+9+y²-10y+25 (Squaring Both Sides)
=> -8x+8y+16=0
OR
=> 8x-8y-16=0
IF IT HELPS, PLEASE MARK IT BRAINLIEST!
As O(x,y) is equidistant from P(7,1) and R(3,5) :
PO = RO
=> √(7-x)²+(1-y)² = √(3-x)²+(5-y)²
=> √x²-14x+49+y²-2y+1 = √x²-6x+9+y²-10y+25
=> x²-14x+49+y²-2y+1=x²-6x+9+y²-10y+25 (Squaring Both Sides)
=> -8x+8y+16=0
OR
=> 8x-8y-16=0
IF IT HELPS, PLEASE MARK IT BRAINLIEST!
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