Find the relation for time period of a simple pendulum exectuting S.H.M.-
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A mass m suspended by a wire of length L is a simple pendulum and undergoes simple harmonic motion for amplitudes less than about 15º. The period of a simple pendulum is T=2π√Lg T = 2 π L g , where L is the length of the string and g is the acceleration due to gravity.
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ANSWER: for a simple pendulum, force constant or spring factor k is proportional to mass m therefore, m cancels out in denominator as well as in numerator.
time pendulum of factor in SHM depends on the force constant k and mass m of the particle: T=2pi√(m/k).
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