find the relation + verify the relation between zero cofficient: x²-x-20
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Just factorize it and you will get the hcf and that will be the relation
sauravshrivastav:
bhai relation nikalna aata hota to puchta hi kyu
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x²-5x+4x-20
x(x-5)+4(x-5)
(x+4)(x-5)
x=(-4):x=5
a=(-4) ß=(5)
a×ß= c/a
-4×5=-20/1
-20= -20
a+ß=-b/a
(-4)+5=-(-1)/1
1=1
hence (-4) and 5 verify the relation between zero cofficient: x²-x-20.
I hope you would like my ans and could be brainiest one.
x(x-5)+4(x-5)
(x+4)(x-5)
x=(-4):x=5
a=(-4) ß=(5)
a×ß= c/a
-4×5=-20/1
-20= -20
a+ß=-b/a
(-4)+5=-(-1)/1
1=1
hence (-4) and 5 verify the relation between zero cofficient: x²-x-20.
I hope you would like my ans and could be brainiest one.
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