Question

Find the relationship between coefficients and zeros of polynomial x2-2x-8

Answer 1

Answer:

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Step-by-step explanation:

X = 4 and -2

sum of zeros = - coeff of x / coeff of x2

product of zeros =

constant term / coeff of x2

Answer 2

Answer:

Here is your answer ll

x²-2x-8

x²-4x+2x-8

x(x-4)+2(x-4)

(x+2)(x-4)

Zeros are 4&-2

$\alpha + \beta = \frac{ - b}{a}$

=-4+2=-2.

Hope it helps you