Find the relative density of Mercury if its density is 13.6x10³ kg/m³
Answers
Answered by
3
R.D.=density of mercy/density of water at 4°C
R.D.=13600/1000
R.D.=13.6
R.D.=13600/1000
R.D.=13.6
Answered by
4
In order to find relative density we use water as it's divident. So we have 1000 kg/m^3 the density of water divided with it:
13.6 x 10^3 / 1000
makes it 13.6 x 10
which is 136 kg/m^3
I hope this helps!
13.6 x 10^3 / 1000
makes it 13.6 x 10
which is 136 kg/m^3
I hope this helps!
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