Question

find the remainder
1) 3x²+x-1 divided by x+1
2) 3x⁴-3x³-3x-1 divided by x-1
3)x⁴+x³-2x²+x+1 divided by x-1
4) 4x³+4x²-x-1 divided by 2x+1​

Answer 1

Step-by-step explanation:

ANSWER:-

1) 3x²+x-1 divided by x+1

x+1=0

x = -1

Placing the factor,

3(-1)²+(-1)-1

= 3-2

= 1 is the answer

2) 3x⁴-3x³-3x-1 divided by x-1

x-1 = 0

x = 1

Placing the value,

3(1)⁴-3(1)³-3(1)-1

= 3-3-3-1

= -4 is the answer

3)x⁴+x³-2x²+x+1 divided by x-1

x-1=0

x = 1

Placing the values,

(1)⁴+(1)³-2(1)²+1

= 1+1-2+1

= 1 is the answer

4) 4x³+4x²-x-1 divided by 2x+1

2x+1=0

2x= -1

$x = \frac{ - 1}{2}$

Placing the values,

$4 {( \frac{ - 1}{2} )}^{3} + 4{( \frac{ - 1}{2}) }^{2} - ( \frac{ - 1}{2} ) - 1$

$4 \times \frac{ - 1}{8} + 4 \times \frac{1}{4} + \frac{1}{2} - 1$

$\frac{ - 1}{2} + \frac{1}{2} - 1$

$= - 1$

is the answer.