Find the remainder 15^23-23^23is divided by 19
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a^n + b^n / a+b
= 0 remainder
When n is odd
15^23 + 23^23/19
N is 23 I.e odd
15+23=38
Which is divisible by 19
So remainder is 0
Alternate Method :
= 0 remainder
When n is odd
15^23 + 23^23/19
N is 23 I.e odd
15+23=38
Which is divisible by 19
So remainder is 0
Alternate Method :
Formula: Remainder(A^n + B^n/ A+B )=0 When n=odd
Here Rem(15^23+23^23/ 19)
N is odd
so , 15+23= 38
and 38 is divisible by 19
so Remainder: 0
Or :
(A^n +b^n) is divisible by a+b when n is odd
So a=15 b =23 n=23
A+b = 38
Which can by divided by 19. So remainder will be 0.
Hope This Helps :)
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0
Answer:
Step-by-step explanation:
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