Question

Find the remainder 15^23-23^23is divided by 19

Answer 1

a^n + b^n / a+b 
= 0 remainder 
When n is odd 
15^23 + 23^23/19 
N is 23 I.e odd
15+23=38 
Which is divisible by 19 
So remainder is 0

Alternate Method :

Formula: Remainder(A^n + B^n/ A+B )=0 When n=odd

Here Rem(15^23+23^23/ 19)

N is odd

so , 15+23= 38

and 38 is divisible by 19

so Remainder: 0

Or :

(A^n +b^n) is divisible by a+b when n is odd

So a=15 b =23 n=23

A+b = 38

Which can by divided by 19. So remainder will be 0.

Hope This Helps :)

Answer 2

Answer:

Step-by-step explanation:

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