Question

Find the remainder. (2y² - 3y + 5) ÷ (2y -1)

1️⃣ 4
2️⃣ 8
3️⃣ 6
4️⃣ 10​

Answer 1

Remainder => 4

hope it helps !!

Answer 2

$\bold{2 {y}^{2} - 3y + 5 \div 2y - 1}$

$= > \frac{2 {y}^{2} - 3y + 5 }{2y - 1} = 4(Remainder) \:$

we get quotient(Q)=y-1

Remainder(R)=4

Correct option is :

1️⃣4 ✓

2️⃣8

3️⃣6

4️⃣10

CHECK:-

$</strong><strong>\</strong><strong>b</strong><strong>o</strong><strong>l</strong><strong>d</strong><strong>{</strong><strong>\</strong><strong>b</strong><strong>o</strong><strong>x</strong><strong>e</strong><strong>d</strong><strong>{</strong><strong>Dividend</strong><strong>=Divisor × Quotient+Remainder</strong><strong>}</strong><strong>}</strong><strong>$

$2 {y}^{2} - 3y + 5 = (2y - 1)(y - 1) + 4$

$= > 2 {y}^{2} - 2y - y + 1 + 4$

$= > 2 {y}^{2} - 3y + 5$