find the remainder 3x^3-4x^2+7x-5 divided by (x-3)and(x+3)
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Let p ( x ) = 3x^3 - 4x^2 + 7x - 5
When p ( x ) is divided by x - 3 the remainder is p ( 3 )
So
p ( 3 ) = 3x^3 - 4x^2 + 7x - 5
= 3 ( 3 )^3 - 4 ( 3 )^2 + 7 ( 2 ) - 5
= 3 × 27 - 4 × 9 + 7 × 2 - 5
= 81 - 36 + 14 - 5
= 54
So the remainder is 54.
Similarly you can solve for p ( - 3 ) .
Hope it helps you ..!!
✌
Let p ( x ) = 3x^3 - 4x^2 + 7x - 5
When p ( x ) is divided by x - 3 the remainder is p ( 3 )
So
p ( 3 ) = 3x^3 - 4x^2 + 7x - 5
= 3 ( 3 )^3 - 4 ( 3 )^2 + 7 ( 2 ) - 5
= 3 × 27 - 4 × 9 + 7 × 2 - 5
= 81 - 36 + 14 - 5
= 54
So the remainder is 54.
Similarly you can solve for p ( - 3 ) .
Hope it helps you ..!!
✌
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