Find the remainder by using remainder theorem when ( 2y +1 ) ³ - 6 ( 3-4y ) - 10 is divisible by ( 2y - 1 )
Answers
Answered by
0
Answer:
p(x)=x
3
−6x
2
+2x−4 and
g(x)=1−
2
3
x
1−
2
3
x=0
=>
2
3
x=1
=>x=
3
2
By, remainder theorem, the remainder when p(x) divided by g(x) is p(
3
2
)
Thus,
p(
3
2
)=(
3
2
)
3
−6(
3
2
)
2
+2(
3
2
)−4
=
27
8
−
9
6×4
+
3
4
−4
=
27
8
−
9
8
+
3
4
−4
=
27
8−24+36−108
=
27
−136
This is your answer
MAKE MY BRAINLY
Answered by
0
Answer:
Given
P(y) = 4y^3-12y^2+5y-4
g(y) = 2y-1
by remainder theorem
2y-1 = 0
2y = 1
y = 1/2
therefore,
p(1/2) = 4×(1/2)^3-12(1/2)^2+5(1/2)-4
p(1/2) = 4x 1/8 - 12×1/4 + 5/2 -4
p(1/2) = 1/2 - 3 +5/2 -4
p(1/2) = -8/2 = -4
Hence, (-4) is the remainder when p(y) = 4y^3-12y^2+5y-4.
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