Find the remainder for x^2018+2018 divided by x-1
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g(x)=x-1
so x-1=0 therefore x=1
p(1)=x2018 +2018
=1*2018+2018
=2019
so x-1=0 therefore x=1
p(1)=x2018 +2018
=1*2018+2018
=2019
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