Question

Find the remainder of
A)0
B)1
C)1+2+3+....+2018
D) 2018/2017.
Pls with steps.
only ans will be reported.​

Answer 1

Answer:

$= \frac{ {1}^{2017} + {2}^{2017} + {3}^{2017} + ..... + {2018}^{2017} }{2017}$

$= \frac{ {20}^{18} }{2018} \\ \\ \\ = 670$

Hope it will be helpful :)...✍️

Answer 2

$\huge\red{Answer}$

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☆☞ [ Verified answer ]☜☆

$</p><p></p><p>\begin{gathered}= \frac{ {20}^{18} }{2018} \\ \= 670\end{gathered}=20182018=670</p><p></p><p>$

jai siya ram☺ __/\__

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