Question

find the remainder of polynomial 4y^3+3y^2-5y+1 is divided by2y+3

Answer 1

#Hello friend
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Let p(x)=4y³+3y²-5y+1

g(x)=2y+3

2y+3=0

y= -3/2

We can solve it using reminder theorem

p(-3/2)=4(-3/2)³+3(-3/2)²-5(-3/2)+1

= (-108/8)+(-27/4)+(15/2)+1

=(-108-54+60+8)/8

= -194/8

= -97/4

The remainder is -97/4

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#Hope it helps

Answer 2

Answer:

wvaish

Ace

953 answers

335K people helped

#Hello friend

______________________________________

Let p(x)=4y³+3y²-5y+1

g(x)=2y+3

2y+3=0

y= -3/2

We can solve it using reminder theorem

p(-3/2)=4(-3/2)³+3(-3/2)²-5(-3/2)+1

= (-108/8)+(-27/4)+(15/2)+1

=(-108-54+60+8)/8

= -194/8

= -97/4

The remainder is -97/4

Step-by-step explanation: