Question

find the remainder when 1^2013+2^2013+3^2013+.....2012^2013 is divisible by 2013?

plzz tell me fast friends
best answer will be marked brainliest

Answer 1

The answer is 0. there will be no remainder left.

I'll explain how

we know right,,

a^3+b^3 = (a+b)(a^2+b^2-ab)
llrly for all odd powers of a&b ,,,(a+b) is always a factor
a^n +b^n ,,,,. (a+b) is factor of this for all odd value of n

This concept we will be using in this!!

(1)^2013+ (2012)^2013= (1+2012)=2013 is factor,

in ,,(2)^2013+(2011)^2013 = (2+2011)= 2013 will be factor

that means we can take 2013 from every term,,,and hence taking 2013 common from numerator,,,,,we can cancel with denominator,,&hence remainder will be 0,as it is divisible

Answer 2

Answer:

find the remainder when 1^2013+2^2013+3^2013+.....2012^2013 is divisible by 2013?

plzz tell me fast friends

best answer will be marked brainliest

Above is the answer