Math, asked by AditiChauhan125, 1 year ago


find the remainder when

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Answered by POWERranger2
1
 \sqrt[x + 1]{x ^{2} + 3x^{2} + 3x + 1}
........x³ + x²

0. +. 2x² + 3x +1
...........2x² + 2x

0+ x+1
........x+1

0

r=0
q=x²+2x+1
Answered by Anonymous
0

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