Question

find the remainder when 3x^3-4x^2+7x-5 is divided by (x+3) by remainder theorem​

Answer 1

Answer:

x+3=0

x=-3

Putting -3 in place of x

=2*-3^3 - 4*-3^2+ 7*(-3) -5

= -18 - 12 + -21 - 5

=30 + (-26)

=30-26

=4

Thus, The remainder is 4.

Hope it helps :D

Answer 2

Answer:

zero of (X+3)=0

x=-3

Remainder=3×(-3)^3-4(-3)^2+7(-3)-5

=-81-36-21-5

=-143