Question

Find the remainder when
4x^3 -3x^2+2x-4 is divisible by x-1 ​

Answer 1

Answer:

-1

Step-by-step explanation:

Reminder is:

4x^3-4x^2+x^2-x+3x-3-1=4x^2(x-1)+x(x-1)+3(x-1)-1=

(x-1)(4x^2+x+3)+ (-1)

Answer 2

Answer:

-1

Step-by-step explanation:

$4 {x}^{3 } - 4 {x}^{2} + {x}^{2} - x + 3x - 3 - 1 = 4 {x}^{2} (x - 1) + x(x - 1) + 3(x - 1) - 1 = \\ (x - 1)(4 {x}^{2} ) + ( - 1)$

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