Question

find the remainder when 4x^3-3x-2 is divided by x-1

Answer 1

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Answer 2

Answer :

By remainder therom :

$x - 1 = 0 \\ x = 1 \\ \\ p(x) = 4 {x}^{3} - 3x - 2 \\ p(1) = 4 ({1})^{3} - 3(1) - 2 \\ p(1) = 4 - 3 - 2 \\ p(1) = 1 - 2 \\ p(1) = - 1$