find the remainder when 4x power 3 - 3 x power2 plus 4 x - 2 is divided by (i) x-3 (ii) x-5
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Answer:
(i) 91 (ii) 443
Step-by-step explanation:
Given f(x) = 4x^3-3x^2+4x-2
• Use the zero product rule
(i) x-3
x-3=0 (zero product rule)
Therefore x=3
Putting x=3 in f(x), you get remainder = 91
(ii) x-5
x-5=0 (zero product rule)
Therefore x=5
Putting x=5 in f(x), you get remainder= 443
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