find the remainder when 4y^3+4y^2-y-1 is divided by 2y+1
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The reminder is 0.
Hope this helps you dear...
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Hope this helps you dear...
Plz mark my answer brainliest if you find it useful...
^_^
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Answered by
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by reminder theorem
zero of 2y+1 is....
let's find
2y+1=0
2y=-1
y=-1/2
p(y)= 4y^3+4y^2-y-1
p(-1/2)= 4×(-1/2)^3 + 4×(-1/2)^2 -(-1/2) - 1
=4×-1/8 + 1 + 1/2 - 1 (1 get cancelled)(-4/8= -1/2)
= -1/2 +1/2
= 0 answer...
reminder is 0 ...
zero of 2y+1 is....
let's find
2y+1=0
2y=-1
y=-1/2
p(y)= 4y^3+4y^2-y-1
p(-1/2)= 4×(-1/2)^3 + 4×(-1/2)^2 -(-1/2) - 1
=4×-1/8 + 1 + 1/2 - 1 (1 get cancelled)(-4/8= -1/2)
= -1/2 +1/2
= 0 answer...
reminder is 0 ...
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