Question

find the remainder when 7x³+6x²-5x+4 is divided by 3/4.​

Answer 1

Answer:

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Step-by-step explanation:

13x³+2x²-29x+14

Step-by-step explanation:

4x³ -7x²+9 +3x² -5x+4+7x³ -11x+1 + 6x² -13x​

=13x³+2x²-29x+14

Answer 2

Answer:

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Step-by-step explanation:

Here, g(x)=3x−1. To apply Remainder theorem, (3x−1) should be converted to (x−a) form.

∴3x−1=31(3x−1)=x−31∴g(x)=(x−31)

By remainder theorem, r(x)=p(a)=p(31)

p(x)=x3−6x2+2x−4⇒p(31)=(31)3−6(31)2+2(31)−4

=271−96+32−4=271−18+18−108=