find the remainder when (9^10+6) is divided by 8
Answers
Answered by
1
Answer:
If (x±1)ⁿ is divided by x,the remainder is (±1)ⁿ.
Now 9^6 - 11 = (8+1)^6 - 11
When it is divided by 8, remainder is
= + 1 – 11 = – 10
When – 10 is divided by 8, remainder = – 2
i.e. – 2 + 8 = 6
Similar questions