Question

find the remainder when f(x)= x³-6x²+2x-4 is divided by g(x)= 1-3x .

Answer 1

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Here's your answer...


Refer the attachment...

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Answer 2

g(x)=1-3x
g(x)=0
1-3x=0
X=1/3
f(x)=x^3-6x^2+2x-4
f(1/3)=(1/3)^3-6×(1/3)^2+2×(1/3)-4
=-107/27

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