Question

Find the remainder when P(x)=2x³-3x²+x-1 is divided by x-1 by remainder theorem method

Answer 1

Answer:

Step-by-step explanation:

Answer 2

The remainder is - 1

Given :

P(x) = 2x³ - 3x² + x - 1 is divided by x - 1

To find :

The remainder

Solution :

Step 1 of 3 :

Write down the given polynomials

Here it is given that P(x) = 2x³ - 3x² + x - 1 is divided by x - 1

P(x) = 2x³ - 3x² + x - 1

Let g(x) = x - 1

Step 2 of 3 :

Find zero of g(x)

For Zero of g(x) we have

g(x) = 0

⇒ x - 1 = 0

⇒ x = 1

Step 3 of 3 :

Find the remainder

By Remainder Theorem the required Remainder when P(x) is Q(x) is

$\sf = P( 1)$

$\sf = 2 \times {( 1)}^{ 3} - 3 \times {( 1)}^{2} + 1 - 1$

$\sf = 2 - 3 + 1 - 1$

$\sf = - 1$

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