Question

find the remainder,when p(x) is divided by g(x) p(x)=x³-6x²+9x+3,g(x)=x-1

Answer 1

$p(x) = x {}^{3} - 6x {}^{2} + 9x + 3 \\ g(x) = x - 1 \\ by \: remainder \: theorem \\ x - 1 = 0 \\ x = 1 \\ so \: remainder = p(1) \\ = 1 {}^{3} - 6 \times 1 {}^{2} + 9 \times 1 + 3 \\ = 1 - 6 + 9 + 3 \\ = 13 - 6 \\ = 7$
•°• Remainder =7

Answer 2

This is ur answer.
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