Math, asked by rajikarthik010506, 7 months ago

Find the remainder when p(x)=x^3-6x^2+14x-3 is divided by g(x)=1-2x and verify the result by long division

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Answers

Answered by ajai2005
2

Answer

4.1/5

87

Given, g(x) = 1 - 2x = 0 i.e x = 1/2 ----------------- (i)

p(x) = x^3-6x^2+14x-3

- 6x^2 - 1

_________________

1 - 2x ) x^2 - 6x^2 + 2x - 4 (

12x^2 - 6x^2

_____________

- 11x^3 + 2x - 4

+ 2x - 1

_______________

- 11x^3 - 3

We have got remainder as - 11x^3 - 3 (we know that x = 1/2 in (i)

= -11/8 - 3/1

= -11 - 24 /8

= -35/8

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Answered by Anonymous
13

Hope this helps you....

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