Question

find the remainder when p(x) =x^3-6x^2+2x-4 is divided by (1-2x), by using remainder theorem and verify the result by actual division​

Answer 1

Step-by-step explanation:

p(x) = x^3-6x^2+2x-4

1-2x=0

2x=1

x=1/2

p(1/2)=(1/2)^3-6(1/2)^2+2(1/2)-4

p(1/2)=(1/8)-6(1/4)+(2/2)-4

p(1/2)=(1/8)-(6/4)+1-4

p(1/2)=1/8-3/2-3

p(1/2) =8-12-3/8

p(1/2) =-15

I'm not sure bcoz same chapter is going on for me..hope this helps you