Question

find the remainder when p(x) =x cube - 6x square + 2x - 4 is divided by 3x -1 [use remainder theorem]​

Answer 1

Answer:

Let,g(x)=0.Then,

3x-1=0

3x=1

x=1/3

By remainder theorem we know that when p(x) is divided by (3x-1) then the remainder is p(1/3)

Now,p(1/3)=(x^3-6x^2+2x-4)

=(1/3)^3-6×(1/3)^2+2×1/3-4

=1/27-6×1/9+2/3-4

=1/27-6/9+2/3-4

=(1-18+18-108)/27,[ 1-18+18-108/27 because LCM

of 27,9and3 is 27]

=(1-108)/27

= -107/27. ---Answer