Question

Find the Remainder when p(x) = x3 -5x is divided by g(x) = -1+ x

Answer 1

Answer:

P(x) can be written as

P(x)=(x−3)Q(x)+6

As P(x) is an odd function  

Hence,P(−x)=−P(x)⇒P(−3)=−P(3)=−6

Let P(x)=Q(x  

2

−9)+ax+b

(where  Q  is quotient and (ax+b)=g(x)=remainder)  

Now P(3)=3a+b=6

P(−3)=−3a+b=−6

Hence, b=0 and a=2

Hence, g(x)=2x⇒g(2)=4

Step-by-step explanation:

Answer 2

Answer:

when P(x) is divided by (x-a) remainder is P(a)

P(x) = x^3 - 5x

a= 1

P(a) = 1^3 - 5*1

= 1 - 5

= -4