find the remainder when p(x)=x⁴+2x³-3x²+x-1 is divided by (x-2) Also find p(2)
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Remainder is 21 if p(x)=x⁴+2x³-3x²+x-1 divided by (x-2)
P(2) = 21
Given:
- p(x)=x⁴+2x³-3x²+x-1 divided by (x-2)
To Find:
- Remainder
- p(2)
Solution:
- Remainder theorem if P(x) is divided by (x -a ) then P(a) is the remainder
Using Long division:
x³ +4x² + 5x +11
x- 2 ) x⁴+2x³-3x²+x-1 (
x⁴-2x³
______
4x³-3x²+x-1
4x³-8x²
________
5x²+x-1
5x²-10x
______
11x - 1
11x - 22
_______
21
Remainder is 21
p(x)=x⁴+2x³-3x²+x-1
P(2) = 2⁴+2(2)³-3(2)²+2-1
= 16 + 16 - 12 + 1
= 21
P(2) = 21
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