find the remainder when p(x)= x4 - 3x square +2x+6 is divided by q(x) = X - 2
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Answer:
x - 2 = 0
x = 2
p (x) = x^4 - 3x ^2 + 2x + 6
p(2) = 2^4 - 3(2)^2 + 2(2) + 6
p(2) = 16 - 12 + 4 + 6
p (2) = 4 + 4 + 6
p(2) = 14
Remainder is 14
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