Math, asked by shrutishah15128, 9 months ago

solve the following simultaneous
equation
i) 13x - 12y = 29; 12x - 13y = 21​

Answers

Answered by Anjali00000007
4

Answer:

x= 5, y= 3

Step-by-step explanation:

13x- 12y= 29 .....( 1 )

12x- 13y= 21 .....( 2 )

Multiplying eqn ( 1 ) by 12

we get,

156x - 144y = 348 ....( 3 )

Multiplying eqn ( 2 ) by 13

we get,

156x - 169y = 273 ....( 4 )

Subtracting eqn ( 3 ) and ( 4 )

we get,

y = 3

Substituting y = 3 in eqn ( 1 )

13x - 12( 3 ) = 29

13x - 36 = 29

13x = 29+36 = 65

x = 65/13

x = 5

Therefore the value of x is 5 and that of y is 3.

Answered by MysticPetals
7

Question : -

Solve the following simultaneous equations

13x-12y=29 , 12x-13y=21

Solution : -

Let 13x-12y=29 --------(1)

Let 12x-13y=21 ---------(2)

Multiply equation (1) by 12 and equation (2) by 13

✭ 12 (13x-12y)=12*29

✭13 (12x-13y)=13*21

=> 156x - 144y = 348

156x - 169y = 273

__________

25 y = 75

_________

y = 75/25

y = 3

By substituting y=3 in equation (1) , we get

13x-12 (3) = 29

13x-36=29

13x=29+36

13x = 65

x=65/13

x = 5

Therefore the solution set = {5,3}

For further information, refer the attachment!

__________________

Attachments:
Similar questions