Question

find the remainder when p(y)=y³+y²+2y+3 is divided by y+2​

Answer 1

i hope this answer is useful for you..

Answer 2

Answer:

-5 is the remainder when P(y) is divided by y +2.

Step-by-step explanation:

Explanation:

According to the given question we need to find out the remainder when

P(y) = $y^3 + y^2 + 2y + 3$ is divided by y+2.

Step 1:

On dividing $y^3 + y^2 + 2y + 3$ by y +2,

              y+2   )$y^3 + y^2 + 2y + 3$($y^2$ +y +4

                        $y^3 +2y^2$

                       -      -                    

                              - $y^2$ + 2y +3

                                $y^2 +2y$

                                                     

                                     +4y + 3

                                       4y + 8  

                                       -    -            

                                             - 5

Step 2:

Now , we check weather -5 is correct or not.

So, from the question we have P(x) = $y^3 + y^2 + 2y + 3$

and y + 2 = 0

⇒y = -2

⇒ P(-2) = $(-2)^3+(-2)^2 + 2(-2) +3$

⇒-8 +4 -4 + 3 = -5.

Final answer:

Hence, the remainder is - 5.

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