Find the remainder when polynomial p(x) =6x^3-7x^2+8x+1 is divided by g(x) =x+1...?
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Let g (x)=0
So x+1=0
x=-1
put x=-1 in p (x)
p (-1)=6 (-1)^3-7 (-1)^2+8 (-1)+1
=-6-7-8+1
=-20
So remainder is '20
So x+1=0
x=-1
put x=-1 in p (x)
p (-1)=6 (-1)^3-7 (-1)^2+8 (-1)+1
=-6-7-8+1
=-20
So remainder is '20
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