Math, asked by jasmin239, 1 year ago

find the remainder when the polynomial p( x) =x ^61 + 61 is divided by x-1 ...please answer fast

Answers

Answered by Anonymous
5
hello here is your answer by Sujeet yaduvanshi,

Given that,


polynomial. x^61+61


Now,
F(x)=x-1
f(x)=x-1=0
x=1

then,

putting the value of x in required polynomial,

x^61+61

(1)^61+61


1+61

62



Hence,
Required Remainder 62


that's all
Answered by Anonymous
4
Let see your answer !!!!!

let \: p(x) = x ^{61}  + 61 \\  \\ f(x) = x  - 1 \\  \\  =  > 0 = x - 1 \\  \\  =  >  - x =  - 1 \\  \\  =  > x = 1

By remainder theorem


p(1) = 1 ^{61}  + 61 \\  \\  = 1 + 61 \\  \\  = 62

Hence , the remainder is 62.




Thanks :)))))
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