Question

find the remainder when x*11-1 is divided by (x-1)​

Answer 1

0 is the remainder
I hope this helps you

Answer 2

$\displaystyle\huge\red{\underline{\underline{Solution}}}$

TO DETERMINE

$\sf{The \: remainder \: when \: ( {x}^{11} - 1) \: is \: divided \: by \: (x-1)}$

CALCULATION

$\sf{Let \: \: \: \: f(x) \: = {x}^{11} - 1 }$

and

$\sf{g(x) = x - 1}$

$\sf{For \: the \: zero \: of \: the \: polynomial \: \: g(x) \: \: we \: have }$

$\sf{g(x) = 0}$

$\implies \sf{x - 1 = 0 \: }$

$\implies \sf{x = 1 \: }$

Hence by the Remainder Theorem

the remainder

$\sf{ when \: ( {x}^{11} - 1) \: is \: divided \: by \: (x-1) \: \: is}$

$\sf{f(1) \: = {(1)}^{11} - 1 }$

$\sf{ = 1 - 1\: }$

$\sf{ = 0\: }$

RESULT

$\boxed{ \sf{ \: Hence \: the \: required \: Remainder \: = \: \: 0 \: \: }}$

━━━━━━━━━━━━━━━━

LEARN MORE FROM BRAINLY

Find the remainder

when x³-ax²+6x-a is divided by x - a

https://brainly.in/question/5714646