Question

Find the remainder when x^2-ax^2+6x-a is divided by (x-a) ​

Answer 1

Step-by-step explanation:

x-a=0

x=a

x²-ax²+6x-a=f(a)

a²-a(a)²+6a-a=fa

a²-a³+5a is the remainder

Answer 2

Answer:

Here's your answer

By remainder theorem

x-a=0

x= a

$p(x) = {x}^{2} - a {x}^{2} + 6x - a \\ \\ p(a) = {a}^{2} - {a}^{3} + 6a - a \\ \\ = {a}^{2} - {a}^{3} + 5a$

Hope it helps ✌✌....