find the remainder when x^3+2x^2+3x+1 is dividef by x+1
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Answered by
1
Answer:
R=2x+1
Step-by-step explanation:
hope this helps.........
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Answered by
1
By using the remainder theorem
x+1=0
x=1
now,
p(x)= x^3+2x^2+3x+1
p(1)= 1^3 +2*1^2+3*1+1
p(1)= 1+2*2+3+1
=1+4+4
=6
hence 6 is the remainder
hope it helps...
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