Question

Find the remainder when x^3+3x^2+3x+1 is divided by x-1/2.
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Answer 1

Answer:

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Answer 2

Given

x³+3x²+3x+1 is polynomial divided by $x-\frac{1}{2}$

To find

The remainder

Solution

Let p(x) =x³+3x²+3x+1

&

g(X)= $x-\frac{1}{2}$

$\implies\:x-\frac{1}{2}=0$

$\therefore\:x=\frac{1}{2}$

Now putting the value g(X) in p(X)

p(x) =x³+3x²+3x+1

=> $\frac{(1}{2)}^3+3\frac({1}{2})^2+3\frac{1}{2}$

=> $\frac{{1}{8}}+\frac{{3}{4}}+\frac{3}{2}+1$

=>$\frac{27}{8}$

Hence ,the remainder is $\frac{27}{8}$