Question

Find the remainder, when x^4+4x^3-5x^2-6x+7 is divided by x-3
Sol=let f(x)=x^4+4x^3-5x^2-6x+7 and zero of x-3 is 3
By the remainder theorm,f(x)=f(3)
f(3)=(3)^4+4(3)^3-5(3)^2-6(3)+7
=81+108-45-18+7
=133
There fore ,133 is remainder

Answer 1

Answer:

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