Question

find the remainder when x cube + 3 X square + 3 X + 1 is divided by X reminder theorem using remainder theorem​

Answer 1

Answer:

$let f(x) = {x}^{3} + 3 {x}^{2} + 3x + 1 \\ g(x) = x \\ \: zero \: of \: g(x) = 0 \\ therefore \: remainder \: = f(0) = {0}^{3} + 3 {0}^{2} + 3(0) + 1 = 0 + 0 + 0 + 1 = 1$

Answer 2

Answer:-

• $$\begin{lgathered}let f(x) = {x}^{3} + 3 {x}^{2} + 3x + 1 \\ g(x) = x \\ \: zero \: of \: g(x) = 0 \\ therefore \: remainder \: = f(0) = {0}^{3} + 3 {0}^{2} + 3(0) + 1 = 0 + 0 + 0 + 1 = 1\end{lgathered}$$..........