Question

find the remainder when x cube + 3 X square + 3 X + 1 is divided by x minus one by two linear polynomial

Answer 1

hope you have asked this method

Answer 2

here is your answer

$p(x) = {x}^{3} + 3 {x}^{2} + 3x + 1 \\ g(x) = x - 1 \\ g(1) = 0 \: \: \: \: (because \: 1 - 1 = 0) \\ by \: factor \: theorm \: \\ putting \: \: x = 1 \: in \: equation \: \\ = {(1)}^{3} + {3(1)}^{2} + 3(1) + 1 \\ 1 + 3 + 3 + 1 \\ = 8$
8 is remainder

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