find the remainder when x cube + 3 X square + 3 X + 1 is divided by 5 + 2 x
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first take out the zeros
5+2x=0
2x=-5
X=-5\2
now,
p(X)=(-5/2)^3. +3(-5/2)^2+3(-5/2)+1
= -125/8 + 3(125/8)+3(-5/2)+1
= -125/8 +125/8-15/2+1
=-15/2 +1
=-13/2 ans
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