Question

find the remainder when x cube -ax square +6x - a is divided by x-a

Answer 1

Hi there !!

Given,
to find the reaminder of the polynomial
x³ - ax² + 6x - a when it is divided by x - a

since , x - a = 0. [ Reaminder theorem ]
x = a

Substituting the values of x = a in place of x , we have ,

f(a) = (a)³ - (a)(a)² + 6(a) - a

f(a) = a³ - a³ + 6a - a = 5a

Thus,
the remainder is 5a