Question

find the remainder when x cube minus a x square + 6 x minus A is divided by x minus A​

Answer 1

Answers

Brainly User

Let the polynomial be =

p(x) = x³-ax²+6x-a

Then g(x) = x-a

To Find : It's remainder when p(x) is divided by g(x) .

Solution :

Consider g(x) = 0

x-a=0

x = a

Put x = a in p(x)

p(x) = x³-ax²+6x-a

= a³-a×a²+6a-a

= 5a

hope this helps you.

pls mark as brainliest